JEE MAIN - Mathematics Hindi (2019 - 10th April Evening Slot - No. 6)
अगर $$\int {{x^5}} {e^{ - {x^2}}}dx = g\left( x \right){e^{ - {x^2}}} + c$$, जहां c एकीकरण का स्थायी है, तो $$g$$(-1) के बराबर है :
1
- 1
$$ - {5 \over 2}$$
$$ - {1 \over 2}$$
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