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JEE MAIN - Mathematics Hindi (2018 - 16th April Morning Slot - No. 6)

$$\lim\limits_{x \rightarrow 0} \frac{(27+x)^{\frac{1}{3}}-3}{9-(27+x)^{\frac{2}{3}}}$$ बराबर है :
$$\frac{1}{3}$$
$$-\frac{1}{3}$$
$$-\frac{1}{6}$$
$$\frac{1}{6}$$

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