JEE MAIN - Mathematics Hindi (2017 - 9th April Morning Slot - No. 2)
बाइनोमियल विस्तार में x−5 का गुणांक
$${\left( {{{x + 1} \over {{x^{{2 \over 3}}} - {x^{{1 \over 3}}} + 1}} - {{x - 1} \over {x - {x^{{1 \over 2}}}}}} \right)^{10}},$$ जहां x $$ \ne $$ 0, 1, है :
$${\left( {{{x + 1} \over {{x^{{2 \over 3}}} - {x^{{1 \over 3}}} + 1}} - {{x - 1} \over {x - {x^{{1 \over 2}}}}}} \right)^{10}},$$ जहां x $$ \ne $$ 0, 1, है :
1
4
$$-$$ 4
$$-$$ 1
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