JEE MAIN - Mathematics Hindi (2017 - 8th April Morning Slot - No. 10)
$$\tan ^{-1}\left[\frac{\sqrt{1+x^{2}}+\sqrt{1-x^{2}}}{\sqrt{1+x^{2}}-\sqrt{1-x^{2}}}\right]$$
$$|x|<\frac{1}{2}, x \neq 0$$, का मान है :
$$\frac{\pi}{4}+\frac{1}{2} \cos ^{-1} x^{2}$$
$$\frac{\pi}{4}+\cos ^{-1} x^{2}$$
$$\frac{\pi}{4}-\frac{1}{2} \cos ^{-1} x^{2}$$
$$\frac{\pi}{4}-\cos ^{-1} x^{2}$$
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