JEE MAIN - Mathematics Hindi (2016 - 9th April Morning Slot - No. 8)
$$x \in \mathbf{R}, x \neq 0, x \neq 1$$ के लिए माना $$f_{0}(x)=\frac{1}{1-x}$$ तथा $$f_{n+1}(x)=f_{0}\left(f_{n}(x)\right), n=0,1,2, \ldots$$ है, तो $$f_{100}(3)+f_{1}\left(\frac{2}{3}\right)+f_{2}\left(\frac{3}{2}\right)$$ बराबर है :
$$\frac{8}{3}$$
$$\frac{5}{3}$$
$$\frac{4}{3}$$
$$\frac{1}{3}$$
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