JEE MAIN - Mathematics Hindi (2015 (Offline) - No. 9)
समाकल $$\int \frac{\mathrm{d} x}{x^{2}\left(x^{4}+1\right)^{3 / 4}}$$ बराबर है :
$$ - {\left( {{x^4} + 1} \right)^{{1 \over 4}}} + c$$
$$ - {\left( {{{{x^4} + 1} \over {{x^4}}}} \right)^{{1 \over 4}}} + c$$
$$ {\left( {{{{x^4} + 1} \over {{x^4}}}} \right)^{{1 \over 4}}} + c$$
$$ {\left( {{x^4} + 1} \right)^{{1 \over 4}}} + c$$
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