JEE MAIN - Mathematics Bengali (2022 - 29th July Morning Shift - No. 12)
$$\left\{ {(x,y):|x - 1| \le y \le \sqrt {5 - {x^2}} } \right\}$$ ক্ষেত্রের ক্ষেত্রফল হল ঃ
$${5 \over 2}{\sin ^{ - 1}}\left( {{3 \over 5}} \right) - {1 \over 2}$$
$${{5\pi } \over 4} - {3 \over 2}$$
$${{3\pi } \over 4} + {3 \over 2}$$
$${{5\pi } \over 4} - {1 \over 2}$$
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