JEE MAIN - Mathematics Bengali (2022 - 29th July Evening Shift - No. 7)
অবকলন সমীকরণ $${{dy} \over {dx}} = {{x + y - 2} \over {x - y}}$$ এর সমাধান $$(2.1)$$ এবং $$(k + 1,2)k > 0$$ বিন্দুগামী হলে তাহা হবে
$$2{\tan ^{ - 1}}\left( {{1 \over k}} \right) = {\log _e}({k^2} + 1)$$
$${\tan ^{ - 1}}\left( {{1 \over k}} \right) = {\log _e}({k^2} + 1)$$
$$2{\tan ^{ - 1}}\left( {{1 \over {k + 1}}} \right) = {\log _e}({k^2} + 2k + 2)$$
$$2{\tan ^{ - 1}}\left( {{1 \over k}} \right) = {\log _e}\left( {{{{k^2} + 1} \over {{k^2}}}} \right)$$
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