JEE MAIN - Mathematics Bengali (2022 - 28th July Morning Shift - No. 9)
যদি $$y = y(x),x \in (0,\pi /2)$$ হল অবকল সমীকরণ $$\left( {{{\sin }^2}2x} \right){{dy} \over {dx}} + (8{\sin ^2}2x + 2\sin 4x)y = 2{e^{ - 4x}}(2\sin 2x + \cos 2x)$$ যেখানে, $$y(\pi /4) = {e^{ - \pi }}$$, তবে $$y(\pi /6)$$ এর মান হবে ঃ
$${2 \over {\sqrt 3 }}{e^{ - 2\pi /3}}$$
$${2 \over {\sqrt 3 }}{e^{2\pi /3}}$$
$${1 \over {\sqrt 3 }}{e^{ - 2\pi /3}}$$
$${1 \over {\sqrt 3 }}{e^{2\pi /3}}$$
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