JEE MAIN - Mathematics Bengali (2022 - 25th June Evening Shift - No. 5)

$$\mathop {\lim }\limits_{x \to {\pi \over 2}} \left( {{{\tan }^2}x\left( {{{(2{{\sin }^2}x + 3\sin x + 4)}^{{1 \over 2}}} - {{({{\sin }^2}x + 6\sin x + 2)}^{{1 \over 2}}}} \right)} \right)$$ -এর মান
$${1 \over {12}}$$
$$ - {1 \over {18}}$$
$$ - {1 \over {12}}$$
$${1 \over 6}$$

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