JEE MAIN - Mathematics Bengali (2022 - 25th June Evening Shift - No. 13)

$${\tan ^{ - 1}}\left( {{{\cos \left( {{{15\pi } \over 4}} \right) - 1} \over {\sin \left( {{\pi \over 4}} \right)}}} \right)$$ -এর মান :
$$ - {\pi \over 4}$$
$$ - {\pi \over 8}$$
$$ - {{5\pi } \over {12}}$$
$$ - {{4\pi } \over 9}$$

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