JEE MAIN - Mathematics Bengali (2022 - 24th June Morning Shift - No. 11)
যদি $$y{{dx} \over {dy}} = 2x + {y^3}\left( {y + 1} \right){e^y},\,x\left( 1 \right) = 0$$, অবকল সমীকরণটির সমাধান $$x = x\left( y \right)$$ হয়, তাহলে $$x\left( e \right)$$ এর মান হবে :
$${e^3}\left( {{e^e} - 1} \right)$$
$${e^e}\left( {{e^3} - 1} \right)$$
$${e^2}\left( {{e^e} + 1} \right)$$
$${e^e}\left( {{e^2} - 1} \right)$$
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