JEE MAIN - Chemistry (2025 - 8th April Evening Shift - No. 3)
Match the LIST-I with LIST-II
| LIST-I | LIST-II |
|---|---|
| A. Carbocation | I. Species that can supply a pair of electrons. |
| B. C-Free radical | II. Species that can receive a pair of electrons. |
| C. Nucleophile | III. sp2 hybridized carbon with empty p-orbital. |
| D. Electrophile | IV. sp2/sp3 hybridized carbon with one unpaired electron. |
Choose the correct answer from the options given below:
A-IV, B-II, C-III, D-I
A-II, B-III, C-I, D-IV
A-III, B-IV, C-I, D-II
A-III, B-IV, C-II, D-I
Explanation
(A) Carbocation $\rightarrow \mathrm{sp}^2$ hybridised carbon with empty P-orbital
_8th_April_Evening_Shift_en_3_1.png)
(B) $\quad$ Carbon free radical $\rightarrow \mathrm{sp}^2 / \mathrm{sp}^3$ hybridised carbon with one unpaired electron.
_8th_April_Evening_Shift_en_3_2.png)
(C) Nuecleophile $\rightarrow$ species of that can supply a pair of electron.
(D) Electrophile $\rightarrow$ species that can receive a pair of electron.
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