JEE MAIN - Chemistry (2025 - 8th April Evening Shift - No. 2)
Match the LIST-I with LIST-II
| LIST-I (Complex/ Species) | LIST-II (Shape & magnetic moment) |
|---|---|
| A. [Ni(CO)4] | I. Tetrahedral, 2.8 BM |
| B. [Ni(CN)4]2– | II. Square planar, 0 BM |
| C. [NiCl4]2– | III. Tetrahedral, 0 BM |
| D. [MnBr4]2– | IV. Tetrahedral, 5.9 BM |
Choose the correct answer from the options given below:
Explanation
(A) $\left[\mathrm{Ni}(\mathrm{CO})_4\right], \mathrm{Ni}^0:[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^2$
Valence orbitals of $\mathrm{Ni}^0$ in pre-hybridisation state :
_8th_April_Evening_Shift_en_2_1.png)
Tetrahedral, Diamagnetic, $\mu=0$ B.M.
(B) $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}, \mathrm{Ni}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^0$
Valence orbitals of $\mathrm{Ni}^{+2}$ in pre-hybridisation state :
_8th_April_Evening_Shift_en_2_2.png)
Square planar, Diamagnetic, $\mu=0$ B.M.
(C) $\left[\mathrm{NiCl}_4\right]^{2-}, \mathrm{Ni}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^0$
Valence orbitals of $\mathrm{Ni}^{+2}$ in ground state :
_8th_April_Evening_Shift_en_2_3.png)
Tetrahedral, paramagnetic, $\mu=\sqrt{8}=2.8$ B.M.
(D) $\left[\mathrm{MnBr}_4\right]^{2-}, \mathrm{Mn}^{+2}:[\mathrm{Ar}] 3 \mathrm{~d}^5$
Valence orbitals of $\mathrm{Mn}^{+2}$ in ground state :
_8th_April_Evening_Shift_en_2_4.png)
Tetrahedral, paramagnetic, $\mu=\sqrt{35}=5.9$ B.M.
Comments (0)
