JEE MAIN - Chemistry (2025 - 8th April Evening Shift - No. 19)
Match the LIST-I with LIST-II
| LIST-I (Reagent) | LIST-II (Functional Group detected) |
|---|---|
| A. Sodium bicarbonate solution | I. double bond/unsaturation |
| B. Neutral ferric chloride | II. carboxylic acid |
| C. ceric ammonium nitrate | III. phenolic - OH |
| D. alkaline KMnO4 | IV. alcoholic - OH |
Choose the correct answer from the options given below:
A-II, B-III, C-I, D-IV
A-II, B-IV, C-III, D-I
A-III, B-II, C-IV, D-I
A-II, B-III, C-IV, D-I
Explanation
(1) Carboxylic acid gives efferve scence with sodium bicarbonate solution
(2) Phenolic-OH gives voilet coloured complex with Neutral $\mathrm{FeCl}_3$.
(3) Alcoholic-OH gives Red colour with cerric ammonium Nitrate.
(4) When alkaline $\mathrm{KMnO}_4$ reacts with an unsaturated compound (Alkene or alkyne) the purple colour of $\mathrm{KMnO}_4$ solution disappears, indicating positive test for unsaturation.
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