JEE MAIN - Chemistry (2025 - 7th April Morning Shift - No. 18)
Reaction $\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$ is a first order reaction. It was started with pure A
| t/min | Pressure of system at time t/mm Hg |
|---|---|
| 10 | 160 |
| $\infty$ | 240 |
Which of the following option is incorrect?
Initial pressure of A is 80 mm Hg
The reaction never goes to completion
Partial pressure of A after 10 minute is 40 mm Hg
Rate constant of the reaction is $1.693 \mathrm{~min}^{-1}$
Explanation
_7th_April_Morning_Shift_en_18_1.png)
$$\begin{aligned} &\begin{aligned} & \mathrm{P}_{\infty}=3 \mathrm{P}_0=240 \\ & \quad \mathrm{P}_0=80 \mathrm{~mm} \text { of } \mathrm{Hg} \\ & \mathrm{Kt}=\ln \left(\frac{\mathrm{P}_{\infty}-\mathrm{P}_0}{\mathrm{P}_{\infty}-\mathrm{Pt}}\right) \\ & \mathrm{K} \times 10=\ln \left(\frac{240-80}{240-160}\right) \\ & \mathrm{K}=\frac{\ln 2}{10}=0.0693 \mathrm{~min}^{-1} \end{aligned}\\ &\text { Option (3) is incorrect } \end{aligned}$$
Comments (0)
