JEE MAIN - Chemistry (2025 - 7th April Morning Shift - No. 17)
When a salt is treated with sodium hydroxide solution it gives gas X . On passing gas X through reagent Y a brown coloured precipitate is formed. X and Y respectively, are
$\mathrm{X}=\mathrm{NH}_3$ and $\mathrm{Y}=\mathrm{HgO}$
$\mathrm{X}=\mathrm{NH}_4 \mathrm{Cl}$ and $\mathrm{Y}=\mathrm{KOH}$
$\mathrm{X}=\mathrm{NH}_3$ and $\mathrm{Y}=\mathrm{K}_2 \mathrm{HgI}_4+\mathrm{KOH}$
$\mathrm{X}=\mathrm{HCl}$ and $\mathrm{Y}=\mathrm{NH}_4 \mathrm{Cl}$
Explanation
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$\mathrm{NH}_3$ is identify by $\mathrm{K}_2\left[\mathrm{HgI}_4\right]+\mathrm{KOH}$
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