JEE MAIN - Chemistry (2025 - 4th April Morning Shift - No. 5)
Pair of transition metal ions having the same number of unpaired electrons is
$\mathrm{Ti}^{3+}, \mathrm{Mn}^{2+}$
$\mathrm{Ti}^{2+}, \mathrm{Co}^{2+}$
$\mathrm{Fe}^{3+}, \mathrm{Cr}^{2+}$
$\mathrm{V}^{2+}, \mathrm{Co}^{2+}$
Explanation
| Configuration | No. of unpaired e$^-$ | |||
|---|---|---|---|---|
| (1) | $\mathrm{V}^{3+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^3 4 \mathrm{~s}^0$ |
3 |
| $\mathrm{Co}^{2+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^7 4 \mathrm{~s}^0$ |
3 | |
| (2) | $\mathrm{Ti}^{2+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^2 4 \mathrm{~s}^0$ |
2 |
| $\mathrm{Co}^{2+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^7 4 \mathrm{~s}^0$ |
3 | |
| (3) | $\mathrm{Fe}^{3+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{~s}^0$ |
5 |
| $\mathrm{Cr}^{2+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^4 4 \mathrm{~s}^0$ |
4 | |
| (4) | $\mathrm{Ti}^{3+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^1 4 \mathrm{~s}^0$ |
1 |
| $\mathrm{Mn}^{2+}$ | $\Rightarrow$ | $[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{~s}^0$ |
5 |
So $\mathrm{V}^{2+} \& \mathrm{Co}^{2+}$ same number of unpaired electron.
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