JEE MAIN - Chemistry (2025 - 4th April Morning Shift - No. 20)
$X Y$ is the membrane/partition between two chambers 1 and 2 containing sugar solutions of concentration $c_1$ and $c_2\left(c_1>c_2\right) \mathrm{mol} \mathrm{L}^{-1}$. For the reverse osmosis to take place identify the correct condition.
(Here $p_1$ and $p_2$ are pressures applied on chamber 1 and 2 ).
_4th_April_Morning_Shift_en_20_1.png)
A. Membrane/Partition : Cellophane, $\mathrm{p}_1>\pi$
B. Membrane/Partition : Porous, $\mathrm{p}_2>\pi$
C. Membrane/Partition : Parchment paper, $p_1>\pi$
D. Membrane/Partition : Cellophane, $\mathrm{p}_2>\pi$
Choose the correct answer from the option given below:
A and C Only
A and D Only
B and D Only
C Only
Explanation
_4th_April_Morning_Shift_en_20_2.png)
Normal osmosis occurs from (2) to (1)
For reverse osmosis from (1) to (2)
Pressure : $\mathrm{P}_1>\pi$
$\therefore$ Answer [A & C] only
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