JEE MAIN - Chemistry (2025 - 4th April Morning Shift - No. 19)
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$
Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element $(\mathrm{X})$ is
49
81
31
13
Explanation
Size order
$$\begin{aligned} & \mathrm{Al}>\mathrm{Ga} \\ & \mathrm{Al}^{3+}<\mathrm{Ga}^{3+} \end{aligned}$$
Atomic number of Ga is 31
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