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JEE MAIN - Chemistry (2025 - 4th April Morning Shift - No. 11)

Which one of the following complexes will have $\Delta_{\mathrm{o}}=0$ and $\mu=5.96$ B.M?
$\left[\mathrm{FeF}_6\right]^{4-}$
$\left[\mathrm{Mn}(\mathrm{SCN})_6\right]^{4-}$
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$
$\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}$

Explanation

JEE Main 2025 (Online) 4th April Morning Shift Chemistry - Coordination Compounds Question 3 English Explanation 1

$=[-0.4 \times 6+0.6 \times(0)] \Delta_0=-2.4 \Delta_0$

$$\begin{aligned} \text{(2) }\quad & {\left[\mathrm{Mn}(\mathrm{SCN})_6\right]^4} \\ & \mathrm{Mn}^{2+} \Rightarrow 3 \mathrm{~d}^5 4 \mathrm{~s}^0 \end{aligned}$$

JEE Main 2025 (Online) 4th April Morning Shift Chemistry - Coordination Compounds Question 3 English Explanation 2

$$\begin{aligned} & \mu=\sqrt{35} \text { B.M. }=5.96 \text { B.M. } \\ & \text { CFSE }=(-0.4 \times 3+0.6 \times 2) \Delta_0 \\ & \text { So } \Delta_0=0 \end{aligned}$$

(3) $\quad\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{-4} \quad \mathrm{Fe}^{2+} \Rightarrow 3 \mathrm{~d}^6 4 \mathrm{~s}^0$

JEE Main 2025 (Online) 4th April Morning Shift Chemistry - Coordination Compounds Question 3 English Explanation 3

$$\begin{aligned} &\mathrm{CFSE}=-2.4 \Delta_0\\ &\text { (4) }\left[\mathrm{FeF}_6\right]^4 \quad \mathrm{Fe}^{2+} \Rightarrow 3 \mathrm{~d}^6 4 \mathrm{~s}^0 \end{aligned}$$

JEE Main 2025 (Online) 4th April Morning Shift Chemistry - Coordination Compounds Question 3 English Explanation 4

$$\begin{aligned} &\mu=\sqrt{24} \text { B.M. }=4.89 \text { B.M. }\\ &\text { CFSE }=(-0.4 \times 4+0.6 \times 2) \Delta_0=-1.2 \Delta_0 \end{aligned}$$

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