JEE MAIN - Chemistry (2025 - 4th April Evening Shift - No. 17)
The correct order of $\left[\mathrm{FeF}_6\right]^{3-},\left[\mathrm{CoF}_6\right]^{3-},\left[\mathrm{Ni}(\mathrm{CO})_4\right]$ and $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ complex species based on the number of unpaired electrons present is:
$\left[\mathrm{CoF}_6\right]^{3-}>\left[\mathrm{FeF}_6\right]^{3-}>\left[\mathrm{Ni}(\mathrm{CO})_4\right]>\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$
$\left[\mathrm{FeF}_6\right]^{3-}>\left[\mathrm{CoF}_6\right]^{3-}>\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}>\left[\mathrm{Ni}(\mathrm{CO})_4\right]$
$\left[\mathrm{FeF}_6\right]^{3-}>\left[\mathrm{CoF}_6\right]^{3-}>\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}=\left[\mathrm{Ni}(\mathrm{CO})_4\right]$
$\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}>\left[\mathrm{FeF}_6\right]^{3-}>\left[\mathrm{CoF}_6\right]^{3-}>\left[\mathrm{Ni}(\mathrm{CO})_4\right]$
Explanation
_4th_April_Evening_Shift_en_17_1.png)
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