JEE MAIN - Chemistry (2025 - 4th April Evening Shift - No. 13)

' $X$ ' is the number of electrons in $t_{2 g}$ orbitals of the most stable complex ion among $\left[\mathrm{Fe}\left(\mathrm{NH}_3\right)_6\right]^{3+},\left[\mathrm{FeCl}_6\right]^{3-}, \quad\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$ and $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$. The nature of oxide of vanadium of the type $\mathrm{V}_2 \mathrm{O}_{\mathrm{X}}$ is :
Amphoteric
Acidic
Basic
Neutral

Explanation

Most stable is $\left[\mathrm{Fe}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$ due to Chelation effect.

JEE Main 2025 (Online) 4th April Evening Shift Chemistry - Coordination Compounds Question 6 English Explanation

$\mathrm{V}_2 \mathrm{O}_5$ is amphoteric.

Comments (0)

Advertisement