JEE MAIN - Chemistry (2025 - 3rd April Morning Shift - No. 4)
$$ \text { Match the LIST-I with LIST-II } $$
| LIST-I (Molecules/ion) |
LIST-II (Hybridisation of central atom) |
||
|---|---|---|---|
| A. | $$ \mathrm{PF}_5 $$ |
I | $$ \mathrm{dsp}^2 $$ |
| B | $$ \mathrm{SF}_6 $$ |
II | $$ \mathrm{sp}^3 \mathrm{~d} $$ |
| C | $$ \mathrm{Ni}(\mathrm{CO})_4 $$ |
III | $$ \mathrm{sp}^3 \mathrm{~d}^2 $$ |
| D | $$ \left[\mathrm{PtCl}_4\right]^{2-} $$ |
IV | $$ \mathrm{sp}^3 $$ |
$$ \text { Choose the correct answer from the options given below: } $$
A-IV, B-I, C-II, D-III
A-III, B-I, C-IV, D-II
A-II, B-III, C-IV, D-I
A-I, B-II, C-III, D-IV
Explanation
$$\begin{aligned} & \mathrm{PF}_5: 5 \sigma+0 \ell \mathrm{p} \rightarrow \mathrm{sp}^3 \mathrm{~d} \\ & \mathrm{SF}_6: 6 \sigma+0 \ell \mathrm{p} \rightarrow \mathrm{sp}^3 \mathrm{~d}^2 \\ & \mathrm{Ni}(\mathrm{CO})_4: \mathrm{Ni} \rightarrow 0 \end{aligned}$$
In presence of ligand field :-
_3rd_April_Morning_Shift_en_4_1.png)
$$\begin{aligned} &\left[\mathrm{PtCl}_4\right]^{2-}: \mathrm{Pt} \rightarrow+2\\ &\text { In presence of ligand field :- } \end{aligned}$$
_3rd_April_Morning_Shift_en_4_2.png)
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