JEE MAIN - Chemistry (2025 - 3rd April Morning Shift - No. 21)
$$ \text {During estimation of nitrogen by Dumas' method of compound } \mathrm{X}(0.42 \mathrm{~g}) $$
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_________mL of $\mathrm{N}_2$ gas will be liberated at STP. (nearest integer)
(Given molar mass in $\mathrm{g}~ \mathrm{mol}^{-1}: \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{~N}: 14$ )Answer
109
Explanation
M.wt. of given compound = 86
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$$\begin{aligned} &\text { Applying POAC on ' } \mathrm{N} \text { ' }\\ &\begin{aligned} & \mathrm{n}_{\mathrm{X}} \times 2=\mathrm{n}_{\mathrm{N}_2} \times 2 \\ & \frac{0.42}{86}=\mathrm{n}_{\mathrm{N}_2} \\ & \Rightarrow(\text { Volume })_{\mathrm{N}_2} \text { at } \mathrm{STP}=\frac{0.42}{86} \times 22.4 \mathrm{~L} \\ & =0.1108 \mathrm{~L}=110.8 \mathrm{~m} \ell \end{aligned} \end{aligned}$$
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