JEE MAIN - Chemistry (2025 - 3rd April Evening Shift - No. 17)
For electrons in ' 2 s ' and ' 2 p ' orbitals, the orbital angular momentum values, respectively are :
0 and $\sqrt{6} \frac{h}{2 \pi}$
0 and $\sqrt{2} \frac{h}{2 \pi}$
$\sqrt{2} \frac{h}{2 \pi}$ and 0
$\frac{h}{2 \pi}$ and $\sqrt{2} \frac{h}{2 \pi}$
Explanation
The orbital angular momentum for electrons in orbitals is given by the formula:
$ \text{Orbital angular momentum} = \sqrt{\ell(\ell+1)} \frac{\mathrm{h}}{2 \pi} $
For the 2s orbital, the quantum number $\ell$ is 0:
Orbital angular momentum = $\sqrt{0(0+1)} \frac{\mathrm{h}}{2 \pi} = 0$
For the 2p orbital, the quantum number $\ell$ is 1:
Orbital angular momentum = $\sqrt{1(1+1)} \frac{\mathrm{h}}{2 \pi} = \sqrt{2} \frac{\mathrm{h}}{2 \pi}$
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