JEE MAIN - Chemistry (2025 - 2nd April Morning Shift - No. 25)
A transition metal (M) among $\mathrm{Mn}, \mathrm{Cr}, \mathrm{Co}$ and Fe has the highest standard electrode potential $\left(\mathrm{M}^{3+} / \mathrm{M}^{2+}\right)$. It forms a metal complex of the type $\left[\mathrm{M}(\mathrm{CN})_6\right]^{4-}$. The number of electrons present in the $\mathrm{e}_{\mathrm{g}}$ orbital of the complex is ___________.
Answer
1
Explanation
Co has highest standard electrode potential $\left(\mathrm{M}^{+3} / \mathrm{M}^{+2}\right)$ among $\mathrm{Mn}, \mathrm{Cr}, \mathrm{Co}, \mathrm{Fe}$
$\therefore$ Complex is $\left[\mathrm{Co}(\mathrm{CN})_6\right]^4$ and its splitting is as follows.
_2nd_April_Morning_Shift_en_25_1.png)
$\therefore$ electron in $\mathrm{e}_{\mathrm{g}}$ orbital is one.
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