JEE MAIN - Chemistry (2025 - 2nd April Evening Shift - No. 3)

Electronic configuration of four elements A, B, C and D are given below :

(A) $1 s^2 2 s^2 2 p^3$

(B) $1 s^2 2 s^2 2 p^4$

(D) $1 s^2 2 s^2 2 p^2$

Which of the following is the correct order of increasing electronegativity (Pauling's scale)?

$\mathrm{D}<\mathrm{A}<\mathrm{B}<\mathrm{C}$

$\mathrm{A}<\mathrm{B}<\mathrm{C}<\mathrm{D}$

$\mathrm{A}<\mathrm{C}<\mathrm{B}<\mathrm{D}$

$\mathrm{A}<\mathrm{D}<\mathrm{B}<\mathrm{C}$

The electronic configurations of four elements, A, B, C, and D, are presented as follows:

(A) $1s^2 2s^2 2p^3$

(B) $1s^2 2s^2 2p^4$

(D) $1s^2 2s^2 2p^2$

To determine the correct order of increasing electronegativity according to Pauling's scale, analyze the elements as follows:

Nitrogen ($1s^2 2s^2 2p^3$): Electronegativity = 3.0

Oxygen ($1s^2 2s^2 2p^4$): Electronegativity = 3.5

Fluorine ($1s^2 2s^2 2p^5$): Electronegativity = 4.0

Carbon ($1s^2 2s^2 2p^2$): Electronegativity = 2.55

The correct order of increasing electronegativity is:

Carbon (D) < Nitrogen (A) < Oxygen (B) < Fluorine (C)