JEE MAIN - Chemistry (2025 - 2nd April Evening Shift - No. 18)

$$ \text { Match List - I with List - II. } $$

List - I (Purification technique)		List - II (Mixture of organic compounds)
(A)	$$ \text { Distillation (simple) } $$	(I)	Diesel + Petrol
(B)	$$ \text { Fractional distillation } $$	(II)	Aniline + Water
(C)	$$ \text { Distillation under reduced pressure } $$	(III)	Chloroform + Aniline
(D)	$$ \text { Steam distillation } $$	(IV)	Glycerol + Spent-lye

$$ \text { Choose the correct answer from the options given below : } $$

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

The correct matching is:

(A) Simple distillation → (III) Chloroform + Aniline

(B) Fractional distillation → (I) Diesel + Petrol

(D) Steam distillation → (II) Aniline + Water

So the answer is Option A.

Brief rationale:

Simple distillation (A):

• $$bp(\text{CHCl}_3)=61^\circ\text{C},\;bp(\text{C}_6\text{H}_5\text{NH}_2)=184^\circ\text{C}$$

• Δbp is large, so the lower-boiling chloroform distils off cleanly.

Fractional distillation (B):

• Petrol (40–200°C) and diesel (180–360°C) have overlapping but distinct boiling-range cuts.

• A fractionating column resolves them efficiently.

Vacuum distillation (C):

• Glycerol boils ≈290°C at 1 atm—too high for normal distillation.

• Lowering the pressure brings its boiling point down, letting you separate it from the spent-lye.

Steam distillation (D):

• Aniline (bp≈184°C) can be co-distilled with water around 98°C, avoiding thermal decomposition and separating it from the aqueous phase.