JEE MAIN - Chemistry (2025 - 2nd April Evening Shift - No. 12)
Reactant A converts to product D through the given mechanism (with the net evolution of heat):
A → B slow; ΔH = +ve
B → C fast; ΔH = -ve
C → D fast; ΔH = -ve
Which of the following represents the above reaction mechanism?
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Explanation
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$$\mathrm{A} \rightarrow \mathrm{~B}$$ Slow
$\Delta \mathrm{H}=+$ ve $\quad \mathrm{E}_{\mathrm{a}_1} \rightarrow \mathrm{High}$
$$\mathrm{B} \rightarrow \mathrm{C}$$ Fast
$$\begin{aligned} & \Delta \mathrm{H}=-\mathrm{ve} \quad \mathrm{E}_{\mathrm{a}_2} \rightarrow \mathrm{Low} \\ & \mathrm{C} \rightarrow \mathrm{D} \\ & \Delta \mathrm{H}=-\mathrm{ve} \quad \mathrm{E}_{\mathrm{a}_3} \rightarrow \mathrm{Low} \end{aligned}$$
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