JEE MAIN - Chemistry (2025 - 29th January Morning Shift - No. 4)
The correct increasing order of stability of the complexes based on $\Delta_0$ value is :
- I. $[\text{Mn}(\text{CN})_6]^{3-}$
- II. $[\text{Co}(\text{CN})_6]^{4-}$
- III. $[\text{Fe}(\text{CN})_6]^{4-}$
- IV. $[\text{Fe}(\text{CN})_6]^{3-}$
I < II < IV < III
IV < III < II < I
III < II < IV < I
II < III < I < IV
Explanation
$$\begin{array}{ll}
\text { (I) }\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-} & -1.6 \Delta_o \\
\text { (II) }\left[\mathrm{Co}(\mathrm{CN})_6\right]^{4-} & -1.8 \Delta_{\circ} \\
\text { (III) }\left[\mathrm{Fe}(\mathrm{CN})_6\right]^4 & -2.4 \Delta_{\mathrm{o}} \\
\text { (IV) }\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-} & -2.0 \Delta_{\mathrm{o}} \\
\text { I }<\text { II }<\text { IV }<\text { III } &
\end{array}$$
Comments (0)
