JEE MAIN - Chemistry (2025 - 29th January Morning Shift - No. 23)
If A2B is 30% ionised in an aqueous solution, then the value of van't Hoff factor (i) is _______ × 10−1.
Answer
16
Explanation
$$\begin{aligned}
& \mathrm{A}_2 \mathrm{~B} \rightarrow 2 \mathrm{~A}^{+}+\mathrm{B}^{-2} ; \mathrm{y}=3 \\
& \alpha=0.3 \\
& \mathrm{i}=1+(\mathrm{y}-1) \alpha \\
& =1+(3-1)(0.3)=1.6=16 \times 10^{-1}
\end{aligned}$$
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