JEE MAIN - Chemistry (2025 - 29th January Morning Shift - No. 21)
The molar mass of the water insoluble product formed from the fusion of chromite ore (FeCr₂O₄) with Na₂CO₃ in presence of O₂ is ___________ g mol⁻¹.
Answer
160
Explanation
$$\begin{aligned}
&4 \mathrm{FeCr}_2 \mathrm{O}_4+8 \mathrm{Na}_2 \mathrm{CO}_3+7 \mathrm{O}_2 \rightarrow 8 \mathrm{Na}_2 \mathrm{CrO}_4+2 \mathrm{Fe}_2 \mathrm{O}_3+8 \mathrm{CO}_2\\
&\mathrm{Fe}_2 \mathrm{O}_3 \text { is water insoluble, so its molar mass }\\
&\Rightarrow[2 \times 56+3 \times 16] \Rightarrow 160 \mathrm{~g} / \mathrm{mol}
\end{aligned}$$
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