JEE MAIN - Chemistry (2025 - 29th January Morning Shift - No. 14)
Match List - I with List - II.
List - I (Complex) | List - II (Hybridisation & Magnetic characters) |
---|---|
(A) [MnBr4]2- | (I) d2sp3 & diamagnetic |
(B) [FeF6]3- | (II) sp3d2 & paramagnetic |
(C) [Co(C2O4)3]3- | (III) sp3 & diamagnetic |
(D) [Ni(CO)4] | (IV) sp3 & paramagnetic |
Choose the correct answer from the options given below :
Explanation
(A) $\left[\mathrm{MnBr}_4\right]^{2-}$
$\mathrm{Mn}^{+2} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5$
In presence of ligand field
$\Rightarrow \mathrm{sp}^3$ hybridization, paramagnetic in nature
(B) $\left[\mathrm{FeF}_6\right]^{3-}$
$$\mathrm{Fe}^{+3} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^5$$
In presence of ligand field
$\Rightarrow \mathrm{sp}^3 \mathrm{~d}^2$ hybridization, paramagnetic in nature
(C) $\left[\mathrm{Co}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}$
$$\mathrm{Co}^{+3} \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^6$$
In presence of ligand field
$\Rightarrow \mathrm{d}^2 \mathrm{sp}^3$ hybridization, diamagnetic in nature
$$\text { (D) }\left[\mathrm{Ni}(\mathrm{CO})_4\right]$$
$$\mathrm{Ni}^0 \Rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^8 4 \mathrm{~s}^2$$
In presence of ligand field
$\Rightarrow \mathrm{sp}^3$ hybridization, diamagnetic in nature
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