JEE MAIN - Chemistry (2025 - 29th January Evening Shift - No. 7)
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Explanation
Azo dyes are organic compounds that contain an azo bond $(-N=N-)$
(1)
There is no azo bond $-N=N-$ formation in this case.
So, azo dye compound is not formed
(2)
Azo dye $(-N=N-$) is not formed in this reaction.
Benzonitrile reaction with H$_2$SO$_4$, gives benzoic acid product. $-CN$ becomes $-COOH$. Then, reaction with $PCl_5$ gives benzoyl chloride $(C_6H_5COCl)$. Its on reaction with aniline does not give $-N=N-$ type compound. So, azo dye compound is not formed.
(3)
Nitrobenzene on reaction with $\mathrm{Sn} / \mathrm{HCl}$ undergoes reduction reaction to form aniline. $-\mathrm{NO}_2$ is reduced to $-\mathrm{NH}_2$.
Aniline on reaction with $\mathrm{NaNO}_2 / \mathrm{HCl}$ undergoes diazotization reaction to form benzene diazonium chloride.
Nitrobenzene on reaction with So/HCl undergoes reduction reaction to form aniline. $-NO_2$ is reduced to $-NH_2$.
Aniline on reaction with $NaNO_2/HCl$ undergoes diazotization reaction to form benzene diazonium chloride.
$\mathrm{NaNO}_2+\mathrm{HCl} \longrightarrow \mathrm{NaCl}+\mathrm{HNO}_2$
Benzene diazonium chloride (Benzene diazonium salt) on reaction with $\beta$-naphthol and NaOH gives an azo compound.
Azo dye is formed in this reaction
(4)
Azo dye is not formed.
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