JEE MAIN - Chemistry (2025 - 28th January Morning Shift - No. 8)

In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?

A. $\mathrm{n}=1, \mathrm{l}=0, \mathrm{~m}_1=0$

B. $\mathrm{n}=2, \mathrm{l}=0, \mathrm{~m}_1=0$

C. $\mathrm{n}=2, \mathrm{I}=1, \mathrm{~m}_1=1$

D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=1$

E. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=0$

Choose the correct answer from the options given below:

B and C Only
C and D Only
A and B Only
D and E Only

Explanation

orbital
$\mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0$ 1s
$\mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0$ 2s
$\mathrm{C}: \mathrm{n}=3, \ell=1, \mathrm{~m}_{\ell}=1$ 3p
$\mathrm{D}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=1$ 3d
$\mathrm{E}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=0$ 3d

In absence of electric and magnetic fields, all orbitals of 3d are degenerate

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