JEE MAIN - Chemistry (2025 - 28th January Morning Shift - No. 7)
The products A and B in the following reactions, respectively are
$\mathrm{A} \stackrel{\mathrm{Ag}-\mathrm{NO}_2}{\longleftrightarrow} \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow{\mathrm{AgCN}} \mathrm{B}$
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{ONO}, \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CN}$
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NO}_2, \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CN}$
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{ONO}, \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NC}$
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NO}_2, \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NC}$
Explanation
$$\mathrm{\mathop {C{H_3} - C{H_2} - C{H_2} - N{O_2}}\limits_{(A)} \buildrel {Ag - N{O_2}} \over
\longrightarrow C{H_3} - C{H_2} - C{H_2} - Br\buildrel {AgCN} \over
\longrightarrow \mathop {C{H_3} - C{H_2} - C{H_2} - NC}\limits_{(B)}}$$
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