JEE MAIN - Chemistry (2025 - 28th January Morning Shift - No. 25)
Quantitative analysis of an organic compound (X) shows following % composition.
C : $14.5 \%$
Cl : 64.46%
H: 1.8 %
(Empirical formula mass of the compound $(\mathrm{X})$ is _________ $\times 10^{-1}$
(Given molar mass in $\mathrm{g} \mathrm{~mol}^{-1}$ of $\mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16, \mathrm{Cl}: 35.5$)
Answer
1655
Explanation
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$$\begin{aligned} & \text { Empiricial formula }=\mathrm{C}_2 \mathrm{H}_3 \mathrm{Cl}_3 \mathrm{O}_2 \\ & \text { Mass }=165.5 \\ & \text { Mass }=1655 \times 10^{-1} \end{aligned}$$
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