JEE MAIN - Chemistry (2025 - 28th January Morning Shift - No. 22)
Consider the following sequence of reactions:
_28th_January_Morning_Shift_en_22_1.png)
11.25 mg of chlorobenzene will produce ___________$\times 10^{-1} \mathrm{mg}$ of product B.
(Consider the reactions result in complete conversion.)
[Given molar mass of $\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{N}$ and Cl as $12,1,16,14$ and $35.5 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively]
Answer
93
Explanation
_28th_January_Morning_Shift_en_22_2.png)
$$\begin{aligned} & \frac{11.25 \times 10^{-3}}{112.5}=\frac{x \times 10^{-1} \times 10^{-3}}{93} \\ & x \times 10^{-1}=93 \times 0.1 \\ & x=93 \mathrm{mg} \end{aligned}$$
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