JEE MAIN - Chemistry (2025 - 28th January Evening Shift - No. 6)

Match List-I with List-II.

List - I (Saccharides) List - II (Glycosidic-linkages found)
(A) Sucrose (I) α 1 $-$ 4
(B) Maltose (II) α 1 $-$ 4 and α 1 $-$ 6
(C) Lactose (III) α 1 $-$ β 2
(D) Amylopectin (IV) β 1 $-$ 4

Choose the correct answer from the options given below :

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
(A)-(IV), (B)-(II), (C)-(I), (D)-(III)

Explanation

(A) Sucrose $\rightarrow \alpha_1-\beta_2$ Glycosidic linkage

(B) Maltose $\rightarrow \alpha$ 1-4 Glycosidic linkage

(C) Lactose $\rightarrow \beta$ 1-4 Glycosidic linkage

(D) Amylopectin $\rightarrow \alpha$ 1-4 and $\alpha$ 1-6 Glycosidic linkage

$$\mathrm{A}-\mathrm{III}, \mathrm{~B}-\mathrm{I}, \mathrm{C}-\mathrm{IV}, \mathrm{D}-\mathrm{II}$$

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