JEE MAIN - Chemistry (2025 - 28th January Evening Shift - No. 19)
Concentrated nitric acid is labelled as $75 \%$ by mass. The volume in mL of the solution which contains 30 g of nitric acid is ______________.
Given : Density of nitric acid solution is $1.25 \mathrm{~g} / \mathrm{mL}$.
32
40
55
45
Explanation
$\% \mathrm{w} / \mathrm{w}$ of $\mathrm{HNO}_3=75 \%$
means 100 gm of solution containing 75 g of $\mathrm{HNO}_3$
$\&\left(\frac{\mathrm{gm}}{\mathrm{m}_1}\right)_{\text {solution }}=1.25=\frac{100 \mathrm{gm}}{\mathrm{V}}$
$\mathrm{V}_{\mathrm{ml}}$ of 100 gm solution $=\frac{100}{1.25} \mathrm{ml}$
$\because 75 \mathrm{gm}$ of $\mathrm{HNO}_3$ present in $\frac{100}{1.25} \mathrm{ml}$ solution
$\therefore 30 \mathrm{gm}$ of $\mathrm{HNO}_3$ present in
$$\frac{100}{1.25 \times 75} \times 30=32 \mathrm{ml} \text { solution }$$
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