JEE MAIN - Chemistry (2025 - 28th January Evening Shift - No. 11)
Identify correct conversion during acidic hydrolysis from the following :
(A) starch gives galactose.
(B) cane sugar gives equal amount of glucose and fructose.
(C) milk sugar gives glucose and galactose.
(D) amylopectin gives glucose and fructose.
(E) amylose gives only glucose.
Choose the correct answer from the options given below :
Explanation
(A) Starch $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ Glucose
(B) $$\mathrm{\mathop {Cane\,sugar}\limits_{(Sucrose)} \buildrel {{H^ + }/{H_2}O} \over \longrightarrow \mathop {glu\cos e}\limits_{50\% } \, + \mathop {fructose}\limits_{50\% }}$$
(C) $$\mathrm{\mathop {Milk\,sugar}\limits_{(Lactose)} \buildrel {{H^ + }/{H_2}O} \over \longrightarrow glu\cos e\, + \,galactose}$$
(D) Amylopectin $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ Glucose
(E) Amylose $\xrightarrow{\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}}$ Glucose
So, correct options are B, C and E only
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