JEE MAIN - Chemistry (2025 - 24th January Morning Shift - No. 6)
Preparation of potassium permanganate from $\mathrm{MnO}_2$ involves two step process in which the 1st step is a reaction with KOH and $\mathrm{KNO}_3$ to produce
$\mathrm{K}_3 \mathrm{MnO}_4$
$\mathrm{K}_4\left[\mathrm{Mn}(\mathrm{OH})_6\right]$
$\mathrm{K}_2 \mathrm{MnO}_4$
$\mathrm{KMnO}_4$
Explanation
$\mathrm{MnO}_2 \xrightarrow[\mathrm{KNO}_3, \mathrm{\Delta}]{\mathrm{KOH}} \mathrm{K}_2 \mathrm{MnO}_4$
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