JEE MAIN - Chemistry (2025 - 24th January Morning Shift - No. 13)
Which of the following statement is true with respect to $\mathrm{H}_2 \mathrm{O}, \mathrm{NH}_3$ and $\mathrm{CH}_4$ ?
A. The central atoms of all the molecules are $\mathrm{sp}^3$ hybridized.
B. The $\mathrm{H}-\mathrm{O}-\mathrm{H}, \mathrm{H}-\mathrm{N}-\mathrm{H}$ and $\mathrm{H}-\mathrm{C}-\mathrm{H}$ angles in the above molecules are $104.5^{\circ}, 107.5^{\circ}$ and $109.5^{\circ}$, respectively.
C. The increasing order of dipole moment is $\mathrm{CH}_4<\mathrm{NH}_3<\mathrm{H}_2 \mathrm{O}$.
D. Both $\mathrm{H}_2 \mathrm{O}$ and $\mathrm{NH}_3$ are Lewis acids and $\mathrm{CH}_4$ is a Lewis base.
E. A solution of $\mathrm{NH}_3$ in $\mathrm{H}_2 \mathrm{O}$ is basic. In this solution $\mathrm{NH}_3$ and $\mathrm{H}_2 \mathrm{O}$ act as Lowry-Bronsted acid and base respectively.
Choose the correct answer from the options given below:
Explanation
Dipole moment $\quad \mathrm{H}_2 \mathrm{O}>\mathrm{NH}_3>\mathrm{CH}_4$
$\mathrm{H}_2 \mathrm{O} \& \mathrm{NH}_3$ are Lewis Bases
$\mathrm{NH}_3$ act as Lowry- Bronsted base
Hence, A, B & C are correct
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