JEE MAIN - Chemistry (2025 - 24th January Evening Shift - No. 8)
For reaction
_24th_January_Evening_Shift_en_8_1.png)
The correct order of set of reagents for the above conversion is :
$\mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}$
$\mathrm{H}_2 \mathrm{SO}_4, \mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}$
$\mathrm{Br}_2 \mid \mathrm{FeBr}_3, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}$
$\mathrm{Ac}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{Br}_2, \mathrm{NaOH}$
Explanation
_24th_January_Evening_Shift_en_8_2.png)
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