JEE MAIN - Chemistry (2025 - 24th January Evening Shift - No. 7)
Based on the data given below :
$$\begin{array}{ll} \mathrm{E}_{\mathrm{Cr}_2 \mathrm{O}_7^{2-} / \mathrm{Cr}^{3+}}^{\circ}=1.33 \mathrm{~V} & \mathrm{E}_{\mathrm{Cl}_2 / \mathrm{Cl}^{(-)}}^{\circ}=1.36 \mathrm{~V} \\ \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^0=1.51 \mathrm{~V} & \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\circ}=-0.74 \mathrm{~V} \end{array}$$
the strongest reducing agent is :
$\mathrm{Cl}^{-}$
$\mathrm{MnO}_4^{-}$
$\mathrm{Cr}$
$\mathrm{Mn}^{2+}$
Explanation
For strongest reducing agent
Reduction potential should be lowest
Hence Cr is the strongest reducing agent.
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