JEE MAIN - Chemistry (2025 - 24th January Evening Shift - No. 22)
The hydrocarbon $(\mathrm{X})$ with molar mass $80 \mathrm{~g} \mathrm{~mol}^{-1}$ and $90 \%$ carbon has _______ degree of unsaturation.
Answer
3
Explanation
Mass of carbon $=\frac{80 \times 90}{100}=72 \mathrm{gm}$
Number of C-atoms $=\frac{72}{12}=6$
Mass of hydrogen $=\frac{80 \times 10}{800}=8 \mathrm{gm}$
Number of H -atoms $=\frac{8}{1}=8$
So molecular formula $\mathrm{C}_6 \mathrm{H}_8$
D.U. $=6+1-8 / 2=7-4=3$
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