JEE MAIN - Chemistry (2025 - 24th January Evening Shift - No. 12)
In the given structure, number of sp and $\mathrm{sp}^2$ hybridized carbon atoms present respectively are :
_24th_January_Evening_Shift_en_12_1.png)
3 and 5
3 and 6
4 and 5
4 and 6
Explanation
_24th_January_Evening_Shift_en_12_2.png)
Number of sp and $\mathrm{sp}^2$ hybridised carbon atom are 3 and 5.
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