JEE MAIN - Chemistry (2025 - 23rd January Morning Shift - No. 3)
What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol?
(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{Br}$ are $12,1,16,80$ respectively )
(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{Br}$ are $12,1,16,80$ respectively )
6.0 g
10.22 g
20.44 g
4.0 g
Explanation
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$$\begin{aligned} & \text { Moles of phenol }=\frac{2}{94}=0.021 \\ & \therefore \text { Moles of bromine }=0.021 \times 3=0.064 \\ & \therefore \text { Mass of bromine }=0.064 \times 160=10.22 \mathrm{~g} \end{aligned}$$
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