JEE MAIN - Chemistry (2025 - 23rd January Morning Shift - No. 24)
Consider the following sequence of reactions to produce major product (A)
_23rd_January_Morning_Shift_en_24_1.png)
$\begin{aligned} & \text { Molar mass of product }(\mathrm{A}) \text { is } \mathrm{g} \mathrm{~mol}^{-1} \text {. } \\ & \text { (Given molar mass in } \mathrm{g} \mathrm{~mol}^{-1} \text { of } \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16, \mathrm{Br}: 80, \mathrm{~N}: 14, \mathrm{P}: 31 \text { ) }\end{aligned}$
Answer
171
Explanation
_23rd_January_Morning_Shift_en_24_2.png)
Molar mass of product $\left(\mathrm{C}_7 \mathrm{H}_7 \mathrm{Br}\right)(\mathrm{A})$ is $171 \mathrm{~g} \mathrm{~mol}^{-1}$
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